976. Largest Perimeter Triangle

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problem

solution

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class Solution {
public:
    int largestPerimeter(vector<int>& nums) {
        sort(nums.begin(), nums.end());
        int perimeter = 0, n= nums.size();
        for(int i=n-2;i>=1;i--){
            if(nums[i]> nums[i+1] - nums[i-1]){
                perimeter = max(perimeter, nums[i]+ nums[i+1]+nums[i-1]);
            }
        }
        return perimeter;
    }
};

analysis

  • time complexity O(nlogn)
  • space complexity O(1)