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876. Middle of the Linked List

發表於 2023-02-13 | 分類於 leetcode

problem

solution

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class Solution {
public:
ListNode* middleNode(ListNode* head) {
ListNode *slow = head, *fast = head;
while(fast && fast->next ){
fast = fast->next->next;
slow= slow->next;
}
return slow;

}
};

analysis

  • time complexity O(n)
  • speed complexity O(1)
# Linked List # Two Pointers
889. Construct Binary Tree from Preorder and Postorder Traversal
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