844. Backspace String Compare

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problem

solution

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class Solution {
public:
    string process(string s){
        string ret ;
        for(char c:s){
            if(c=='#'){
                if(!ret.empty()) ret.pop_back();
            }
            else ret+=c;
        }
        return ret;
    }
    bool backspaceCompare(string s, string t) {
        string ret, ans;
        string a = process(s), b = process(t);
        return a==b;
    }
};

analysis

  • time complexity O(n)
  • space complexity O(n)