695. Max Area of Island

problem

solution

option 1 - dfs

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
class Solution {
public:
void dfs(vector<vector<int>> & grid, int i, int j, int & area){

int n = grid.size(), m = grid[0].size();
if(i < 0 || j< 0 || i>n-1 || j>m-1 || grid[i][j] == 0 ) return;
grid[i][j] = 0;
area++;
dfs(grid, i+1, j, area);
dfs(grid, i-1, j, area);
dfs(grid, i, j+1, area);
dfs(grid, i, j-1, area);
}
int maxAreaOfIsland(vector<vector<int>>& grid) {
int n = grid.size(), m = grid[0].size();
int ret = 0;
for(int i=0;i<n;++i){
for(int j = 0;j<m;++j){
int area = 0;
dfs(grid, i, j, area);
ret= max(ret, area);
}
}
return ret;
}
};

analysis

  • time complexity O(n*m)
  • space complexity O(n*m)